Anna_03 - 20.01.2016 00:26If the velocity of an object changes from 56 m/s to 85 m/s during a time interval of 13 s, what is the acceleration of the object?

Patrick Simpson - 20.01.2016 00:51Initial velocity of the object (V1) = 56 m/s Final velocity of the object (V2) = 85 m/s Time taken by the object = 13 seconds Then Acceleration of the object = (V2 - V1)/Time taken = (85 - 56)/13 m/s^2 = 29/13 m/s^2 = 2.23 m/s^2 So the final answer is 2.23 meter per square second. I hope the procedure for solving this kind of problems is absolutely clear to you.