Open discussion — free answers and payable offers

Please help! David is 3 year older than Brandon. In 6 years the sum of their ages will be 45 years. find their ages now. Provide a complete algebraic solution.

Mathematics
Devin_6

Devin_6 - 26.01.2016 21:54Please help! David is 3 year older than Brandon. In 6 years the sum of their ages will be 45 years. find their ages now. Provide a complete algebraic solution.

Alexa_78 - 26.01.2016 21:59David 's age = x Brandon 's age = x-3 David 's age in five years = x+6 Brandon 's age in five years = x-3+6 The sum of their ages in five years = x+6 + x-3+6 x + 6 + x - 3 + 6 = 45 2x + 9 = 45 -9 -9 2x = 36 :2 :2 x = 18 x - 3 = 15 David is 18 years old and Brandon is 15 years old

You have to sign in as a teacher to join the discussion and offer your help with this question.
Sign in / Not registered? Sign up

Payable offers

No offers yet

Top