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Twenty-seven members of a west Virginia diet club celebrated the combined loss of top pounds by devouring a very large salad. The salad took two hours to prepare and four hours to eat. I'm fact, the salad was mixed in a swimming pool and included 890 individual vegetables. There were six times as many carrots as heads of lettuce, and there were ten more cucumbers thanheads heads of lettuce. If a head of lettuce weighs two pounds, and a carrot weighs four ounces, and a cucumber weighs one pound, how much did the total salad weigh?

Algebra
Elexis1Emiracle

Elexis1Emiracle - 14.01.2016 08:56Twenty-seven members of a west Virginia diet club celebrated the combined loss of top pounds by devouring a very large salad. The salad took two hours to prepare and four hours to eat. I'm fact, the salad was mixed in a swimming pool and included 890 individual vegetables. There were six times as many carrots as heads of lettuce, and there were ten more cucumbers thanheads heads of lettuce. If a head of lettuce weighs two pounds, and a carrot weighs four ounces, and a cucumber weighs one pound, how much did the total salad weigh?

Amy Davies - 15.01.2016 00:54Let's calculate how many vegetables there were: 890 = carrots + cucumbers + heads of lettuce ... 890 = 6 * heads of lettuce + 10 * heads of lettuce + heads of lettuce ... 890 = 6x + 10x + x = 17x ... x = 890/17. So there were 890/17 heads of lettuce, 6*(890/17) carrots, 10*(890/17) cucumbers. Knowing the weights of each vegetable we can calculate the overall total of the salad multiplying the vegetables' weights and their quantity: (2 pounds * 890/17) + (4 pounds * 6 * 890 / 17) + (1 pound * 10 * 890 / 17) = 1884.70588 pounds

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